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Solucionarioecuacionesdiferencialesdenniszill6edicion



 
 
 
 
 
 
 

Solucionarioecuacionesdiferencialesdenniszill6edicion

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Q:

Can I make a type list readonly and return a random item?

I have a type list that I initialize once and every time I call a function I want it to return a random item.
type list = [] | {item: ‘a list}[]

let init = [‘a’, ‘b’, ‘c’];

let randN = function
| {item} -> Random.int (0, 2)
| [] -> Random.int (0, 2)
| {item} :: _ -> Random.int (0, 2)

init
|> List.choose (fun y -> randN y)
|> List.of_enum

Doing that gives me a compiler error:

The field ‘item’ is used by constructor Random.int in the type ‘int’ but is not exposed in the ‘list’ constructor

Is there a way to accomplish this?

A:

If you are using F# 4.0, there is a more idiomatic way to achieve the same:
// In F#, you can define a function without using a type annotation.
let getRandomElement list =
// In this case, it’s possible to write
// the type of the lambda as {x: string} -> int, but not
// {item: ‘a list} -> int
Random.int (0, 2)
|> fun r -> list |> List.tryPick r

// In F#, it’s idiomatic to use `list` for your variables,
// not `init` as in your case.
let init = [‘a’, ‘b’, ‘c’]
let randN list = getRandomElement list

// The random function returns an F# unit value.
// However, given that you can assign the result to a variable,
// it is normal to write things as a function (albeit
// a small one).
randN init

Note that you need to create a list in order to use tryPick (this is not the case in OCaml). This is because list is a covariant type alias in F#, which means that it’s not possible to convert a
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